JEE Main 2022 · 26 Jun · Shift 2 · Chemistry Q78

← JEE Main 2022 · 26 Jun · Shift 2

ChemistrySingle correct+4 / -1Question 78 of 90

The final product 'C' in the following series of reactions is

Nitrobenzene with (Sn/HCl) gives A, which with NaNO2/HCl gives B, which with β-naphthol/NaOH gives C.

Phenylazo group and OH on different rings of naphthalene (structure A)

Naphthalene drawn vertically; N=N-C6H5 on the lower ring next to the ring fusion and OH lower down on the same ring.

Phenylazo group on one ring and OH on the other ring of naphthalene (structure B)

Naphthalene drawn horizontally; OH at the upper right of the right ring and N=N-C6H5 at the bottom of the left ring next to the fusion.

1-(Phenylazo)-2-naphthol (structure C)

1-(Phenylazo)-2-naphthol: N=N-C6H5 at C-1 and OH at C-2 of the same ring.

Phenylazo group on one ring and OH next to the ring fusion on the other (structure D)

Naphthalene drawn horizontally; N=N-C6H5 on the left ring and OH on the right ring next to the fusion.

Answer and worked solution

Official answer: C

Sequence. Nitrobenzene → aniline (Sn/HCl) → benzenediazonium chloride ( $\mathrm{NaNO_2}$ /HCl) → coupling with β-naphthol at C-1 in alkali: 1-phenylazo-2-naphthol, an orange dye.

(C)

Topics:Diazonium salts Nitro compounds

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JEE Main 2022 · 26 Jun · Shift 2, Chemistry question 78