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JEE Main 2022 · 26 Jun · Shift 1, Physics question 52

A ball of mass 0.5 kg is dropped from the height of 10 m. The height, at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity, is ______ m.

[Use g=10g=10 m/s2^2]

Answer and worked solution

Official answer: 5

Speed 10 m/s after falling v22g=10020=5\dfrac{v^2}{2g}=\dfrac{100}{20}=5 m.

Height 10−5=510-5=5 m.

Answer: 5