JEE Main 2022 · 26 Jun · Shift 1 · Physics Q46

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PhysicsSingle correct+4 / -1Question 46 of 90

In free space, an electromagnetic wave of 3 GHz frequency strikes over the edge of an object of size $\dfrac\lambda{100}$ , where $\lambda$ is the wavelength of the wave in free space. The phenomenon, which happens there will be :

Reflection

Refraction

Diffraction

Scattering

Answer and worked solution

Official answer: D

Size against wavelength. $\lambda=\dfrac{3\times10^8}{3\times10^9}=0.1$ m, so the object is 1 mm, far smaller than $\lambda$ . Such a small obstacle scatters the wave.

(D)

Topics:Diffraction

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JEE Main 2022 · 26 Jun · Shift 1, Physics question 46