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← JEE Main 2022 · 26 Jun · Shift 1
MathematicsInteger+4 / -1Question 27 of 90

JEE Main 2022 · 26 Jun · Shift 1, Mathematics question 27

Let A={n∈N:H.C.F.(n,45)=1}A=\{n\in\mathbb N:\text{H.C.F.}(n,45)=1\} and Let B={2k:k∈{1,2,…,100}}B=\{2k:k\in\{1,2,\dots,100\}\}. Then the sum of all the elements of A∩BA\cap B is ______.

Answer and worked solution

Official answer: 5264

Even numbers 2 to 200 not divisible by 3 or 5.

Inclusion-exclusion. All evens: 10100. Multiples of 6: 6⋅33⋅342=33666\cdot\frac{33\cdot34}2=3366. Multiples of 10: 10⋅20⋅212=210010\cdot\frac{20\cdot21}2=2100. Multiples of 30: 30⋅6⋅72=63030\cdot\frac{6\cdot7}2=630.

Sum. 10100−3366−2100+630=526410100-3366-2100+630=5264.

Answer: 5264