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← JEE Main 2022 · 26 Jun · Shift 1
MathematicsInteger+4 / -1Question 23 of 90

JEE Main 2022 · 26 Jun · Shift 1, Mathematics question 23

Let the common tangents to the curves 4(x2+y2)=94\left(x^2+y^2\right)=9 and y2=4xy^2=4x intersect at the point Q. Let an ellipse, centered at the origin O, has lengths of semi-minor and semi-major axes equal to OQ and 6, respectively. If ee and ll respectively denote the eccentricity and the length of the latus rectum of this ellipse, then le2\dfrac l{e^2} is equal to ______.

Answer and worked solution

Official answer: 4

Common tangents. y=mx+1my=mx+\frac1m touches x2+y2=94x^2+y^2=\frac94 when 1∣m∣1+m2=32\dfrac{1}{|m|\sqrt{1+m^2}}=\dfrac32, i.e. m2=13m^2=\frac13.

Point Q. The tangents y=±x3±3y=\pm\frac x{\sqrt3}\pm\sqrt3 meet at (−3,0)(-3,0), so OQ=3OQ=3.

Ellipse b=3b=3, a=6a=6: e2=34e^2=\frac34, l=2b2a=3l=\frac{2b^2}a=3, so le2=4\dfrac l{e^2}=4.

Answer: 4