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← JEE Main 2022 · 26 Jun · Shift 1
MathematicsSingle correct+4 / -1Question 19 of 90

JEE Main 2022 · 26 Jun · Shift 1, Mathematics question 19

Let f(x)=2cos⁡−1x+4cot⁡−1x−3x2−2x+10f(x)=2\cos^{-1}x+4\cot^{-1}x-3x^2-2x+10, x∈[−1,1]x\in[-1,1]. If [a,b][a,b] is the range of the function ff, then 4a−b4a-b is equal to :

Choose one option
Answer and worked solution

Official answer: B

Monotonic. f′(x)=−21−x2−41+x2−6x−2≤−2−2+4=0f'(x)=-\dfrac2{\sqrt{1-x^2}}-\dfrac4{1+x^2}-6x-2\le-2-2+4=0 on [−1,1][-1,1], so ff decreases.

Ends. f(1)=0+π−3−2+10=π+5=af(1)=0+\pi-3-2+10=\pi+5=a and f(−1)=2π+3π−3+2+10=5π+9=bf(-1)=2\pi+3\pi-3+2+10=5\pi+9=b.

Value. 4a−b=11−π4a-b=11-\pi.

(B)