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← JEE Main 2022 · 26 Jun · Shift 1
MathematicsSingle correct+4 / -1Question 16 of 90

JEE Main 2022 · 26 Jun · Shift 1, Mathematics question 16

If a⃗⋅b⃗=1\vec a\cdot\vec b=1, b⃗⋅c⃗=2\vec b\cdot\vec c=2 and c⃗⋅a⃗=3\vec c\cdot\vec a=3, then the value of [a⃗×(b⃗×c⃗), b⃗×(c⃗×a⃗), c⃗×(b⃗×a⃗)]\left[\vec a\times\left(\vec b\times\vec c\right),\ \vec b\times\left(\vec c\times\vec a\right),\ \vec c\times\left(\vec b\times\vec a\right)\right] is :

Choose one option
Answer and worked solution

Official answer: A

Expand. a⃗×(b⃗×c⃗)=3b⃗−c⃗\vec a\times(\vec b\times\vec c)=3\vec b-\vec c, b⃗×(c⃗×a⃗)=c⃗−2a⃗\vec b\times(\vec c\times\vec a)=\vec c-2\vec a, c⃗×(b⃗×a⃗)=3b⃗−2a⃗\vec c\times(\vec b\times\vec a)=3\vec b-2\vec a.

Dependent. The third vector is the sum of the first two, so the box product is 0.

(A)