JEE Main 2022 · 26 Jun · Shift 1 · Chemistry Q64

ChemistrySingle correct+4 / -1Question 64 of 90

Consider the ions/molecule
$\mathrm{O_2^+,\ O_2,\ O_2^-,\ O_2^{2-}}$
For increasing bond order the correct option is :

\mathrm{O_2^{2-}<O_2^-<O_2<O_2^+}

\mathrm{O_2^-<O_2^{2-}<O_2<O_2^+}

\mathrm{O_2^-<O_2^{2-}<O_2^+<O_2}

\mathrm{O_2^-<O_2^+<O_2^{2-}<O_2}

Answer and worked solution

Official answer: A

Bond orders. $\mathrm{O_2^+}$ 2.5, $\mathrm{O_2}$ 2, $\mathrm{O_2^-}$ 1.5, $\mathrm{O_2^{2-}}$ 1.

Increasing. $\mathrm{O_2^{2-}<O_2^-<O_2<O_2^+}$ .

(A)

Topics:Molecular orbital theory

JEE Main 2022 · 26 Jun · Shift 1, Chemistry question 64