JEE Main 2022 · 25 Jun · Shift 2 · Physics Q53

PhysicsInteger+4 / -1Question 53 of 90

A block of mass 200 g is kept stationary on a smooth inclined plane by applying a minimum horizontal force $F=\sqrt x$ N as shown in figure.

The value of $x=$ ______.

Your answer

Answer and worked solution

Official answer: 12

Balance along the smooth incline: $F\cos60°=mg\sin60°$ , so $F=mg\tan60°=0.2\times10\times\sqrt3=2\sqrt3=\sqrt{12}$ N.

So $x=12$ .

Answer: 12

JEE Main 2022 · 25 Jun · Shift 2, Physics question 53