JEE Main 2022 · 25 Jun · Shift 2 · Physics Q50

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PhysicsSingle correct+4 / -1Question 50 of 90

If $n$ represents the actual number of deflections in a converted galvanometer of resistance $G$ and shunt resistance $S$ . Then the total current $I$ when its figure of merit is $K$ will be :

\dfrac{KS}{(S+G)}

\dfrac{(G+S)}{nKS}

\dfrac{nKS}{(G+S)}

\dfrac{nK(G+S)}S

Answer and worked solution

Official answer: D

Galvanometer current. $I_g=nK$ .

Shunt. $I_gG=(I-I_g)S$ , so $I=I_g\dfrac{G+S}S=\dfrac{nK(G+S)}S$ .

(D)

Topics:Moving coil galvanometer Ammeters and voltmeters

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JEE Main 2022 · 25 Jun · Shift 2, Physics question 50