JEE Main 2022 · 25 Jun · Shift 2 · Physics Q44

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PhysicsSingle correct+4 / -1Question 44 of 90

The interference pattern is obtained with two coherent light sources of intensity ratio 4:1. And the ratio $\dfrac{I_{\max}+I_{\min}}{I_{\max}-I_{\min}}$ is $\dfrac5x$ . Then, the value of $x$ will be equal to :

Answer and worked solution

Official answer: B

Amplitudes $2:1$ , so $I_{\max}\propto9$ and $I_{\min}\propto1$ .

Ratio. $\dfrac{9+1}{9-1}=\dfrac54$ , so $x=4$ .

(B)

Topics:Interference and Young's double slit

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JEE Main 2022 · 25 Jun · Shift 2, Physics question 44