JEE Main 2022 · 25 Jun · Shift 2 · Physics Q36

PhysicsSingle correct+4 / -1Question 36 of 90

The ratio of specific heats $\left(\dfrac{C_p}{C_v}\right)$ in terms of degree of freedom ( $f$ ) is given by :

\left(1+\dfrac f3\right)

\left(1+\dfrac2f\right)

\left(1+\dfrac f2\right)

\left(1+\dfrac1f\right)

Answer and worked solution

Official answer: B

Equipartition. $C_v=\frac f2R$ , $C_p=\left(\frac f2+1\right)R$ , so $\gamma=1+\dfrac2f$ .

(B)

JEE Main 2022 · 25 Jun · Shift 2, Physics question 36