JEE Main 2022 · 25 Jun · Shift 2 · Physics Q34

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PhysicsSingle correct+4 / -1Question 34 of 90

A solid metallic cube having total surface area 24 m $^2$ is uniformly heated. If its temperature is increased by 10°C, calculate the increase in volume of the cube. (Given $\alpha=5.0\times10^{-4}$ °C $^{-1}$ ).

2.4\times10^6

^3

1.2\times10^5

^3

6.0\times10^4

^3

4.8\times10^5

^3

Answer and worked solution

Official answer: B

Cube. $6a^2=24$ m $^2$ , so $a=2$ m and $V=8$ m $^3$ .

Expansion. $\Delta V=3\alpha V\Delta T=3(5\times10^{-4})(8)(10)=0.12$ m $^3=1.2\times10^5$ cm $^3$ .

(B)

Topics:Temperature and thermal expansion

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JEE Main 2022 · 25 Jun · Shift 2, Physics question 34