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← JEE Main 2022 · 25 Jun · Shift 2
MathematicsInteger+4 / -1Question 23 of 90

JEE Main 2022 · 25 Jun · Shift 2, Mathematics question 23

The value of b>3b>3 for which 12∫3b1(x2−1)(x2−4)dx=log⁡e(4940)12\displaystyle\int_3^b\frac1{\left(x^2-1\right)\left(x^2-4\right)}dx=\log_e\left(\frac{49}{40}\right), is equal to ______.

Answer and worked solution

Official answer: 6

Partial fractions. 1(x2−1)(x2−4)=13(1x2−4−1x2−1)\dfrac1{(x^2-1)(x^2-4)}=\dfrac13\left(\dfrac1{x^2-4}-\dfrac1{x^2-1}\right).

Antiderivative. 12∫=log⁡e(x−2)(x+1)2(x+2)(x−1)212\displaystyle\int=\log_e\frac{(x-2)(x+1)^2}{(x+2)(x-1)^2}; at x=3x=3 it is log⁡e45\log_e\frac45.

Solve. We need the value log⁡e4950\log_e\frac{49}{50} at bb; b=6b=6 gives 4⋅498⋅25=4950\dfrac{4\cdot49}{8\cdot25}=\dfrac{49}{50}.

Answer: 6