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← JEE Main 2022 · 25 Jun · Shift 2
ChemistryInteger+4 / -1Question 86 of 90

JEE Main 2022 · 25 Jun · Shift 2, Chemistry question 86

Consider the following reactions :
PCl3+H2O→A+HCl\mathrm{PCl_3+H_2O\rightarrow A+HCl}
A+H2O→B+HCl\mathrm{A+H_2O\rightarrow B+HCl}
The number of ionisable protons present in the product B is ______.

Answer and worked solution

Official answer: 2

Hydrolysis. PCl3\mathrm{PCl_3} hydrolyses stepwise to phosphorous acid, B =H3PO3=\mathrm{H_3PO_3}, i.e. HP(O)(OH)2\mathrm{HP(O)(OH)_2}.

Ionisable protons. Only the two O-H hydrogens; the P-H is not acidic. So 2.

Answer: 2