JEE Main 2022 · 25 Jun · Shift 2 · Chemistry Q76

← JEE Main 2022 · 25 Jun · Shift 2

ChemistrySingle correct+4 / -1Question 76 of 90

In the given reaction

'A' can be

2 A treated with (i) 2 Mg, THF (ii) methyl benzoate (iii) H2O/H+ gives triphenylmethanol, (C6H5)3C-OH.

benzyl bromide

bromobenzene

cyclohexyl bromide

methyl bromide

Answer and worked solution

Official answer: B

Grignard. An ester takes two equivalents of $\mathrm{RMgX}$ : $\mathrm{C_6H_5COOCH_3+2RMgBr}$ gives $\mathrm{C_6H_5C(OH)R_2}$ . To get $\mathrm{(C_6H_5)_3COH}$ , R must be phenyl, so A is bromobenzene.

(B)

Topics:Alcohols Acid derivatives

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JEE Main 2022 · 25 Jun · Shift 2, Chemistry question 76