JEE Main 2022 · 25 Jun · Shift 2 · Chemistry Q61

ChemistrySingle correct+4 / -1Question 61 of 90

The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is:

[Given: The threshold frequency of platinum is $1.3\times10^{15}\ \mathrm s^{-1}$ and $h=6.6\times10^{-34}$ J s.]

3.21\times10^{-14}

6.24\times10^{-16}

8.58\times10^{-19}

9.76\times10^{-20}

Answer and worked solution

Official answer: C

Threshold energy. $E_0=h\nu_0=6.6\times10^{-34}\times1.3\times10^{15}=8.58\times10^{-19}$ J.

(C)

Topics:Photoelectric effect and spectra

JEE Main 2022 · 25 Jun · Shift 2, Chemistry question 61