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JEE Main 2022 · 25 Jun · Shift 1, Physics question 54

A steam engine intakes 50 g of steam at 100°C per minute and cools it down to 20°C. If latent heat of vaporization of steam is 540 cal g−1^{-1}, then the heat rejected by the steam engine per minute is ______ ×103\times10^3 cal.

(Given : specific heat capacity of water : 1 cal g−1^{-1} °C−1^{-1})

Answer and worked solution

Official answer: 31

Heat given up per minute: condensation 50×540=2700050\times540=27000 cal plus cooling 50×1×80=400050\times1\times80=4000 cal.

Total 31×10331\times10^3 cal.

Answer: 31

Topics:Latent heat and phase changeCalorimetry and specific heat
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