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← JEE Main 2022 · 25 Jun · Shift 1
PhysicsSingle correct+4 / -1Question 49 of 90

JEE Main 2022 · 25 Jun · Shift 1, Physics question 49

The difference of speed of light in the two media A and B (vA−vB)(v_A-v_B) is 2.6×1072.6\times10^7 m/s. If the refractive index of medium B is 1.47, then the ratio of refractive index of medium B to medium A is : (Given : speed of light in vacuum c=3×108 ms−1c=3\times10^8\ \mathrm{ms^{-1}})

Choose one option
Answer and worked solution

Official answer: C

Speeds. vB=3×1081.47≈2.041×108v_B=\dfrac{3\times10^8}{1.47}\approx2.041\times10^8, so vA≈2.301×108v_A\approx2.301\times10^8 m s−1^{-1} and nA≈1.304n_A\approx1.304.

Ratio. nBnA=1.471.304≈1.13\dfrac{n_B}{n_A}=\dfrac{1.47}{1.304}\approx1.13.

(C)