JEE Main 2022 · 25 Jun · Shift 1 · Physics Q43

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PhysicsSingle correct+4 / -1Question 43 of 90

The two light beams having intensities I and 9I interfere to produce a fringe pattern on a screen. The phase difference between the beams is $\pi/2$ at point P and $\pi$ at point Q. Then the difference between the resultant intensities at P and Q will be :

2 I

6 I

5 I

7 I

Answer and worked solution

Official answer: B

Resultant. $I_R=I_1+I_2+2\sqrt{I_1I_2}\cos\phi=10I+6I\cos\phi$ .

At P ( $\phi=\frac\pi2$ ): $10I$ . At Q ( $\phi=\pi$ ): $4I$ .

Difference $6I$ .

(B)

Topics:Interference and Young's double slit

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JEE Main 2022 · 25 Jun · Shift 1, Physics question 43