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JEE Main 2022 · 25 Jun · Shift 1, Physics question 34

If force F⃗=3i^+4j^−2k^\vec F=3\hat i+4\hat j-2\hat k acts on a particle having position vector 2i^+j^+2k^2\hat i+\hat j+2\hat k then, the torque about the origin will be :

Choose one option
Answer and worked solution

Official answer: B

Torque. τ⃗=r⃗×F⃗=(2,1,2)×(3,4,−2)=(−2−8, 6+4, 8−3)=−10i^+10j^+5k^\vec\tau=\vec r\times\vec F=(2,1,2)\times(3,4,-2)=(-2-8,\ 6+4,\ 8-3)=-10\hat i+10\hat j+5\hat k.

(B)

Topics:Torque and rotational dynamicsVectors
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