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← JEE Main 2022 · 25 Jun · Shift 1
MathematicsInteger+4 / -1Question 30 of 90

JEE Main 2022 · 25 Jun · Shift 1, Mathematics question 30

The greatest integer less than or equal to the sum of first 100 terms of the sequence 13,59,1927,6581,…\dfrac13,\dfrac59,\dfrac{19}{27},\dfrac{65}{81},\dots is equal to ______.

Answer and worked solution

Official answer: 98

General term. 3n−2n3n=1−(23)n\dfrac{3^n-2^n}{3^n}=1-\left(\dfrac23\right)^n.

Sum. 100−2(1−(23)100)=98+2(23)100100-2\left(1-\left(\frac23\right)^{100}\right)=98+2\left(\frac23\right)^{100}, just above 98.

Answer: 98