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← JEE Main 2022 · 25 Jun · Shift 1
MathematicsSingle correct+4 / -1Question 10 of 90

JEE Main 2022 · 25 Jun · Shift 1, Mathematics question 10

Let E1E_1 and E2E_2 be two events such that the conditional probabilities P(E1∣E2)=12P(E_1|E_2)=\dfrac12, P(E2∣E1)=34P(E_2|E_1)=\dfrac34 and P(E1∩E2)=18P(E_1\cap E_2)=\dfrac18. Then :

Choose one option
Answer and worked solution

Official answer: C

Marginals. P(E2)=1/81/2=14P(E_2)=\dfrac{1/8}{1/2}=\dfrac14, P(E1)=1/83/4=16P(E_1)=\dfrac{1/8}{3/4}=\dfrac16, so P(E1)P(E2)=124P(E_1)P(E_2)=\dfrac1{24}.

Check (C). P(E1∩E2′)=16−18=124P(E_1\cap E_2')=\dfrac16-\dfrac18=\dfrac1{24}. ✓

(A) fails since 18≠124\frac18\ne\frac1{24}; (B) and (D) fail similarly.

(C)