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← JEE Main 2022 · 25 Jun · Shift 1
ChemistryInteger+4 / -1Question 84 of 90

JEE Main 2022 · 25 Jun · Shift 1, Chemistry question 84

The standard entropy change for the reaction
4Fe(s)+3O2(g)→2Fe2O3(s)\mathrm{4Fe(s)+3O_2(g)\rightarrow2Fe_2O_3(s)}
is −550 J K−1-550\ \mathrm{J\,K^{-1}} at 298 K.

[Given : The standard enthalpy change for the reaction is −165 kJ mol−1-165\ \mathrm{kJ\,mol^{-1}}]. The temperature in K at which the reaction attains equilibrium is ______. (Nearest Integer)

Answer and worked solution

Official answer: 300

Equilibrium. ΔG=0\Delta G=0: T=ΔHΔS=−165000−550=300T=\dfrac{\Delta H}{\Delta S}=\dfrac{-165000}{-550}=300 K.

Answer: 300