JEE Main 2022 · 25 Jun · Shift 1 · Chemistry Q81

ChemistryInteger+4 / -1Question 81 of 90

The number of N atoms in 681 g of $\mathrm{C_7H_5N_3O_6}$ is $x\times10^{21}$ . The value of $x$ is ______.

( $N_A=6.02\times10^{23}\ \mathrm{mol^{-1}}$ ) (Nearest Integer)

Your answer

Answer and worked solution

Official answer: 5418

Moles. $\mathrm{C_7H_5N_3O_6}$ (TNT) has $M=227$ , so 681 g is 3 mol, containing 9 mol N atoms.

Atoms. $9\times6.02\times10^{23}=5.418\times10^{24}=5418\times10^{21}$ .

Answer: 5418

JEE Main 2022 · 25 Jun · Shift 1, Chemistry question 81