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JEE Main 2022 · 24 Jun · Shift 2, Physics question 49

Two light beams of intensities in the ratio of 9 : 4 are allowed to interfere. The ratio of the intensity of maxima and minima will be :

Choose one option
Answer and worked solution

Official answer: D

Amplitudes. a1a2=94=32\dfrac{a_1}{a_2}=\sqrt{\dfrac94}=\dfrac32.

Ratio. Imax⁡Imin⁡=(3+2)2(3−2)2=251\dfrac{I_{\max}}{I_{\min}}=\dfrac{(3+2)^2}{(3-2)^2}=\dfrac{25}1.

(D)

Topics:Interference and Young's double slit
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