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JEE Main 2022 · 24 Jun · Shift 2, Physics question 44

A 100 g of iron nail is hit by a 1.5 kg hammer striking at a velocity of 60 ms−160\ \mathrm{ms^{-1}}. What will be the rise in the temperature of the nail if one fourth of energy of the hammer goes into heating the nail ?

[Specific heat capacity of iron =0.42 Jg−1 °C−1=0.42\ \mathrm{Jg^{-1}\,°C^{-1}}]

Choose one option
Answer and worked solution

Official answer: C

Hammer's energy. 12(1.5)(60)2=2700\frac12(1.5)(60)^2=2700 J; one fourth is 675 J.

Temperature rise. ΔT=675100×0.42≈16.07\Delta T=\dfrac{675}{100\times0.42}\approx16.07°C.

(C)

Topics:Calorimetry and specific heat
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