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← JEE Main 2022 · 24 Jun · Shift 2
PhysicsSingle correct+4 / -1Question 37 of 90

JEE Main 2022 · 24 Jun · Shift 2, Physics question 37

What will be the most suitable combination of three resistors A =2 Ω=2\ \Omega, B =4 Ω=4\ \Omega, C =6 Ω=6\ \Omega so that (223)Ω\left(\dfrac{22}3\right)\Omega is equivalent resistance of combination?

Choose one option
Answer and worked solution

Official answer: B

Try (B). A∥B=2×46=43 ΩA\parallel B=\dfrac{2\times4}{6}=\dfrac43\ \Omega; in series with C: 6+43=223 Ω6+\dfrac43=\dfrac{22}3\ \Omega.

(The others give 4+324+\frac32, 8×412\frac{8\times4}{12} and 10×212\frac{10\times2}{12} Ω.)

(B)