JEE Main 2022 · 24 Jun · Shift 2 · Chemistry Q77

ChemistrySingle correct+4 / -1Question 77 of 90

The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents is

(i)

\mathrm{SOCl_2}

(ii) KCN (iii)

\mathrm{H_2/Ni}

\mathrm{Na(Hg)/C_2H_5OH}

(i) HCl (ii)

\mathrm{H_2/Ni}

\mathrm{Na(Hg)/C_2H_5OH}

(i)

\mathrm{SOCl_2}

(ii) KCN (iii)

\mathrm{CH_3NH_2}

(i) HCl (ii)

\mathrm{CH_3NH_2}

Answer and worked solution

Official answer: A

One carbon is added via cyanide.

$\mathrm{SOCl_2}$ : $\mathrm{CH_3CH_2CH_2OH\rightarrow CH_3CH_2CH_2Cl}$ .
KCN: $\mathrm{\rightarrow CH_3CH_2CH_2CN}$ .
$\mathrm{H_2/Ni}$ or $\mathrm{Na(Hg)/C_2H_5OH}$ : $\mathrm{\rightarrow CH_3CH_2CH_2CH_2NH_2}$ , n-butylamine.

(A)

Topics:Amines Cyanides and isocyanides

JEE Main 2022 · 24 Jun · Shift 2, Chemistry question 77