JEE Main 2022 · 24 Jun · Shift 2 · Chemistry Q65

ChemistrySingle correct+4 / -1Question 65 of 90

For a first order reaction, the time required for completion of 90% reaction is 'x' times the half life of the reaction. The value of 'x' is

(Given: $\ln10=2.303$ and $\log2=0.3010$ )

1.12

2.43

3.32

33.31

Answer and worked solution

Official answer: C

First order. $t_{90\%}=\dfrac{2.303}k\log10=\dfrac{2.303}k$ and $t_{1/2}=\dfrac{2.303\log2}k$ .

Ratio. $x=\dfrac1{\log2}=\dfrac1{0.3010}\approx3.32$ .

(C)

Topics:Integrated rate equations Half-life

JEE Main 2022 · 24 Jun · Shift 2, Chemistry question 65