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← JEE Main 2022 · 24 Jun · Shift 1
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JEE Main 2022 · 24 Jun · Shift 1, Physics question 56

When light of frequency twice the threshold frequency is incident on the metal plate, the maximum velocity of emitted electron is v1v_1. When the frequency of incident radiation is increased to five times the threshold value, the maximum velocity of emitted electron becomes v2v_2. If v2=x v1v_2=x\,v_1, the value of xx will be ______.

Answer and worked solution

Official answer: 2

Einstein's equation. 12mv2=hν−hν0\frac12mv^2=h\nu-h\nu_0.

Two cases. 12mv12=hν0\frac12mv_1^2=h\nu_0 and 12mv22=4hν0\frac12mv_2^2=4h\nu_0.

Ratio. v2v1=4=2\dfrac{v_2}{v_1}=\sqrt4=2.

Answer: 2