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PhysicsInteger+4 / -1Question 53 of 90

JEE Main 2022 · 24 Jun · Shift 1, Physics question 53

A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base current changes by 10 μ10\ \muA and the collector current changes by 1.5 mA. The load resistance is 5 kΩ5\ \mathrm{k\Omega}. The voltage gain of the transistor will be ______.

Answer and worked solution

Official answer: 750

Current gain. β=ΔICΔIB=1.5 mA10 μA=150\beta=\dfrac{\Delta I_C}{\Delta I_B}=\dfrac{1.5\text{ mA}}{10\ \mu\text A}=150.

Input resistance. ri=10 mV10 μA=1r_i=\dfrac{10\text{ mV}}{10\ \mu\text A}=1 kΩ.

Voltage gain. AV=βRLri=150×5=750A_V=\beta\dfrac{R_L}{r_i}=150\times5=750.

Answer: 750