JEE Main 2022 · 24 Jun · Shift 1 · Physics Q42

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PhysicsSingle correct+4 / -1Question 42 of 90

The equations of two waves are given by :
$y_1=5\sin2\pi(x-vt)\ \text{cm}$
$y_2=3\sin2\pi(x-vt+1.5)\ \text{cm}$
These waves are simultaneously passing through a string. The amplitude of the resulting wave is :

2 cm

4 cm

5.8 cm

8 cm

Answer and worked solution

Official answer: A

Phase difference. $\phi=2\pi\times1.5=3\pi$ , which is equivalent to $\pi$ : the waves are in antiphase.

Resultant amplitude. $A=\sqrt{5^2+3^2+2(5)(3)\cos3\pi}=5-3=2$ cm.

(A)

Topics:Superposition and interference

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JEE Main 2022 · 24 Jun · Shift 1, Physics question 42