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← JEE Main 2021 · 24 Feb · Shift 1
PhysicsInteger+4 / -1Question 28 of 90

JEE Main 2021 · 24 Feb · Shift 1, Physics question 28

In connection with the circuit drawn below, the value of current flowing through 2 kΩ resistor is _______ ×10−4\times10^{-4} A.

A 10 V cell in series with a 1 kΩ resistor feeding a 5 V Zener diode (reverse biased) connected in parallel with a 2 kΩ resistor.
Answer and worked solution

Official answer: 25

Zener conducts (the 2 kΩ alone would take more than 5 V), so the 2 kΩ resistor sits at 5 V: 52000=2.5\frac5{2000}=2.5 mA =25×10−4=25\times10^{-4} A.

Answer: 25