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← JEE Main 2021 · 24 Feb · Shift 1
PhysicsInteger+4 / -1Question 25 of 90

JEE Main 2021 · 24 Feb · Shift 1, Physics question 25

An inclined plane is bent in such a way that the vertical cross-section is given by y=x24y=\dfrac{x^2}4 where y is in vertical and x in horizontal direction. If the upper surface of this curved plane is rough with coefficient of friction μ = 0.5, the maximum height in cm at which a stationary block will not slip downward is _______ cm.

Answer and worked solution

Official answer: 25

Limiting slope dydx=x2=μ=0.5\frac{dy}{dx}=\frac x2=\mu=0.5, so x=1x=1 m and y=14y=\frac14 m = 25 cm.

Answer: 25