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← JEE Main 2021 · 24 Feb · Shift 1
PhysicsSingle correct+4 / -1Question 13 of 90

JEE Main 2021 · 24 Feb · Shift 1, Physics question 13

A current through a wire depends on time as

i=α0t+βt2i=\alpha_0t+\beta t^2

where α0\alpha_0 = 20 A/s and β = 8 A s−2^{-2}. Find the charge crossed through a section of the wire in 15 s.

Choose one option
Answer and worked solution

Official answer: C

Charge ∫015(20t+8t2)dt=10(225)+83(3375)=2250+9000=11250\displaystyle\int_0^{15}(20t+8t^2)dt=10(225)+\frac83(3375)=2250+9000=11250 C.

(C)