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JEE Main 2021 · 24 Feb · Shift 1, Physics question 4

Moment of inertia (M.I.) of four bodies, having same mass and radius, are reported as ;

I1_1 = M.I. of thin circular ring about its diameter,
I2_2 = M.I. of circular disc about an axis perpendicular to disc and going through the centre,
I3_3 = M.I. of solid cylinder about its axis and
I4_4 = M.I. of solid sphere about its diameter.

Then :

Choose one option
Answer and worked solution

Official answer: D

Values. Ring about a diameter, disc about its axis and solid cylinder about its axis are all 12MR2\frac12MR^2; the solid sphere is 25MR2\frac25MR^2, smaller.

(D)

Topics:Moment of inertiaParallel and perpendicular axis theorems
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