JEE Main 2021 · 24 Feb · Shift 1 · Physics Q2

PhysicsSingle correct+4 / -1Question 2 of 90

Two stars of masses m and 2m at a distance d rotate about their common centre of mass in free space. The period of revolution is :

\dfrac1{2\pi}\sqrt{\dfrac{3Gm}{d^3}}

2\pi\sqrt{\dfrac{d^3}{3Gm}}

2\pi\sqrt{\dfrac{3Gm}{d^3}}

\dfrac1{2\pi}\sqrt{\dfrac{d^3}{3Gm}}

Answer and worked solution

Official answer: B

Reduced problem. $\omega^2=\dfrac{G(m+2m)}{d^3}$ , so $T=2\pi\sqrt{\dfrac{d^3}{3Gm}}$ .

(B)

Topics:Satellites and orbital motion Centre of mass

JEE Main 2021 · 24 Feb · Shift 1, Physics question 2