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← JEE Main 2021 · 24 Feb · Shift 1
MathematicsInteger+4 / -1Question 88 of 90

JEE Main 2021 · 24 Feb · Shift 1, Mathematics question 88

If one of the diameters of the circle x2+y2−2x−6y+6=0x^2+y^2-2x-6y+6=0 is a chord of another circle 'C', whose center is at (2, 1), then its radius is _______.

Answer and worked solution

Official answer: 3

Given circle centre (1, 3), radius 2. Its diameter is a chord of C, so C's radius is d2+22\sqrt{d^2+2^2} with d2=1+4=5d^2=1+4=5: radius 3.

Answer: 3