JEE Main 2021 · 24 Feb · Shift 1 · Mathematics Q76

MathematicsSingle correct+4 / -1Question 76 of 90

The equation of the plane passing through the point (1, 2, −3) and perpendicular to the planes $3x+y-2z=5$ and $2x-5y-z=7$ , is :

6x − 5y + 2z + 10 = 0

11x + y + 17z + 38 = 0

6x − 5y − 2z − 2 = 0

3x − 10y − 2z + 11 = 0

Answer and worked solution

Official answer: B

Normal $(3,1,-2)\times(2,-5,-1)=(-11,-1,-17)$ . Through (1, 2, −3): $11x+y+17z+38=0$ .

(B)

Topics:Equation of a plane

JEE Main 2021 · 24 Feb · Shift 1, Mathematics question 76