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← JEE Main 2021 · 24 Feb · Shift 1
MathematicsSingle correct+4 / -1Question 61 of 90

JEE Main 2021 · 24 Feb · Shift 1, Mathematics question 61

Let f:R→Rf:\mathbf R\to\mathbf R be defined as f(x)=2x−1f(x)=2x-1 and g:R−{1}→Rg:\mathbf R-\{1\}\to\mathbf R be defined as g(x)=x−12x−1g(x)=\dfrac{x-\frac12}{x-1}. Then the composition function f(g(x)) is :

Choose one option
Answer and worked solution

Official answer: A

Compose. f(g(x))=2x−1x−1−1=xx−1f(g(x))=\dfrac{2x-1}{x-1}-1=\dfrac x{x-1}, which is one-one on R−{1}\mathbf R-\{1\} but never takes the value 1: not onto.

(A)