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← JEE Main 2021 · 24 Feb · Shift 1
ChemistryInteger+4 / -1Question 51 of 90

JEE Main 2021 · 24 Feb · Shift 1, Chemistry question 51

4.5 g of compound A (MW = 90) was used to make 250 mL of its aqueous solution. The molarity of the solution in M is x×10−1x\times10^{-1}. The value of xx is _______. (Rounded off to the nearest integer)

Answer and worked solution

Official answer: 2

Molarity 4.5/900.25=0.2\frac{4.5/90}{0.25}=0.2 M =2×10−1=2\times10^{-1}.

Answer: 2