JEE Main 2021 · 24 Feb · Shift 1 · Chemistry Q47

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ChemistrySingle correct+4 / -1Question 47 of 90

'A' and 'B' in the following reactions are :

Aniline is treated with NaNO $_2$ /HCl and then KCN to give (A); (A) with SnCl $_2$ /HCl/H $_3$ O $^+$ gives (B).

Scheme: aniline → (NaNO2/HCl, KCN) (A) → (SnCl2/HCl/H3O+) (B).

(no structures printed for this option)

A: benzenediazonium chloride; B: benzaldehyde

A: benzonitrile; B: chlorobenzene

A: benzonitrile; B: benzaldehyde

Answer and worked solution

Official answer: D

Steps. Diazotisation then KCN (Sandmeyer-type) gives benzonitrile. Stephen reduction (SnCl₂/HCl, then hydrolysis) turns the nitrile into benzaldehyde.

(D)

Topics:Diazonium salts Named reactions

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JEE Main 2021 · 24 Feb · Shift 1, Chemistry question 47