JEE Main 2021 · 24 Feb · Shift 1 · Chemistry Q32

ChemistrySingle correct+4 / -1Question 32 of 90

In Freundlich adsorption isotherm, slope of AB line is :

n with (n, 0.1 to 0.5)

log n with (n > 1)

\log\dfrac1n

with (n < 1)

\dfrac1n

with

\left(\dfrac1n=0\text{ to }1\right)

Answer and worked solution

Official answer: D

Linear form $\log\frac xm=\log k+\frac1n\log P$ : the slope is $\frac1n$ , between 0 and 1.

(D)

Topics:Adsorption

JEE Main 2021 · 24 Feb · Shift 1, Chemistry question 32