JEE Main 2017 · 9 Apr · Shift 1 · Physics Q25

PhysicsSingle correct+4 / -1Question 25 of 90

The acceleration of an electron in the first orbit of the hydrogen atom (n = 1) is :

\dfrac{h^2}{\pi^2m^2r^3}

\dfrac{h^2}{8\pi^2m^2r^3}

\dfrac{h^2}{4\pi^2m^2r^3}

\dfrac{h^2}{4\pi m^2r^3}

Answer and worked solution

Official answer: C

With $mvr=\dfrac h{2\pi}$ , $v=\dfrac h{2\pi mr}$ and
$a=\frac{v^2}r=\frac{h^2}{4\pi^2m^2r^3}.$

JEE Main 2017 · 9 Apr · Shift 1, Physics question 25