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← JEE Main 2017 · 9 Apr · Shift 1
PhysicsSingle correct+4 / -1Question 23 of 90

JEE Main 2017 · 9 Apr · Shift 1, Physics question 23

A single slit of width 0.1 mm is illuminated by a parallel beam of light of wavelength 6000 Å and diffraction bands are observed on a screen 0.5 m from the slit. The distance of the third dark band from the central bright band is :

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Answer and worked solution

Official answer: B

y3=3λDa=3×6×10−7×0.510−4=9×10−3y_3=\dfrac{3\lambda D}a=\dfrac{3\times6\times10^{-7}\times0.5}{10^{-4}}=9\times10^{-3} m = 9 mm.