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← JEE Main 2017 · 9 Apr · Shift 1
PhysicsSingle correct+4 / -1Question 13 of 90

JEE Main 2017 · 9 Apr · Shift 1, Physics question 13

A standing wave is formed by the superposition of two waves travelling in opposite directions. The transverse displacement is given by
y(x,t)=0.5sin⁡(5π4x)cos⁡(200πt).y(x,t)=0.5\sin\left(\frac{5\pi}4x\right)\cos(200\pi t).
What is the speed of the travelling wave moving in the positive xx direction ?

(xx and t are in meter and second, respectively.)

Choose one option
Answer and worked solution

Official answer: A

v=ωk=200π5π/4=160v=\dfrac\omega k=\dfrac{200\pi}{5\pi/4}=160 m/s.