JEE Main 2017 · 9 Apr · Shift 1 · Physics Q5

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A conical pendulum of length 1 m makes an angle θ = 45° w.r.t. Z-axis and moves in a circle in the XY plane. The radius of the circle is 0.4 m and its center is vertically below O. The speed of the pendulum, in its circular path, will be : (Take g = 10 ms $^{-2}$ )

A conical pendulum hung from O on the Z-axis, its string at angle θ to the vertical, the bob moving on a horizontal circle centred at C below O.

0.4 m/s

4 m/s

0.2 m/s

2 m/s

Answer and worked solution

Official answer: D

For a conical pendulum $\tan\theta=\dfrac{v^2}{rg}$ . With θ = 45° and r = 0.4 m, $v^2=0.4\times10=4$ , so $v=2$ m/s.

Topics:Circular motion dynamics

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JEE Main 2017 · 9 Apr · Shift 1, Physics question 5