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← JEE Main 2017 · 9 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 72 of 90

JEE Main 2017 · 9 Apr · Shift 1, Mathematics question 72

The function ff defined by f(x)=x3−3x2+5x+7f(x)=x^3-3x^2+5x+7, is :

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Answer and worked solution

Official answer: A

f′(x)=3x2−6x+5=3(x−1)2+2>0f'(x)=3x^2-6x+5=3(x-1)^2+2>0, so ff is increasing on R\mathbb R.