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← JEE Main 2017 · 9 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 62 of 90

JEE Main 2017 · 9 Apr · Shift 1, Mathematics question 62

The sum of all the real values of xx satisfying the equation 2(x−1)(x2+5x−50)=12^{(x-1)(x^2+5x-50)}=1 is :

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Answer and worked solution

Official answer: C

2(… )=12^{(\dots)}=1 needs (x−1)(x2+5x−50)=0(x-1)(x^2+5x-50)=0. The roots are x=1x=1 and the two real roots of x2+5x−50x^2+5x-50 (discriminant 225), which sum to −5. In total, 1−5=−41-5=-4.